SEC - May, 1997 - Paper 2A Question 2 - Reno Anastasio
2.
a) The moment of a force about a point is equal to the product of the force and the perpendicular distance between the line of action of the force and that point.
(or simply : By
moment of a force I mean the turning effect of a force)
The principle of moments states that when an object is in equilibrium (or balanced), by a number of forces acting on it, the sum of the anticlockwise moments is equal to the sum of the clockwise moments. (4)
b)
ii)
Balance the metre ruler using the masses.
iii)
Measure the distances d1 and d2.
iv)
If possible use different values for the masses
and repeat the experiment.
Then
calculate the anticlockwise moment =
W1 x
d1
and the clockwise moment =
W2 x
d2
They will be found to be approximately equal proving that the principle of moments is true. (6)
ii)
Tension forces in rope = 500 N each as
iii)
Anticlockwise
moments = clockwise moments
FB x 2 m
= (300 N
x 1 m) +
( 700 N x
1.5 m)
FB
=
300 Nm +
1050 Nm
2
m
= 675 N Answer
c (iii)
therefore FA
= 1000 N -
675 N =
325 N
Answer c (iii)
(4)