moon landing was fake 28.000km/hr is NOT yet possible for 1 kg Spacetravel around earth needs 28.000km/hr Conclusion : US-space-travel is FAKE

28.000km/hr is NOT yet possible for 1 kg

It is easier to throw away a bullet of 100 gram, than a canonball of 100 kilogram. So I asked myself... Is there a relation between mass and the maximum speed?

Current Maximum Velocity for some Objects

 Object Current Maximum Velocity foton(0.0...1gram) 300.000 km/sec (speed of light) elektron(-) 250.000 km/sec (20% error - electronmicroscopy) proton(+) 200.000 km/sec (50% error - cyclotron) 0.01 gram 15,8 km/sec = 57.000 km/hr ( Physics News ) 2 gram 24.000 km/hr (NASA) 10 gram 17.000 km/hr (T5) 17 gram 13.000 km/hr (ARF) 1 kilogram 4.000 km/hr (summary of some experiments)

The higher the mass, the lower the maximum speed.
All experiments were done in airless tubes.

Since there is more energy and momentum lost during 1000 seconds (a ballistic rocket), than in the case of 0.001 second (a bullet), and since the laws of physics are the same, i.e. the conservation of energy and momentum,
the current maximum velocity of a rocket is LESS than the current maximum velocity of a bullet in an airless tube. Theoretically, it is possible to get any velocity by the use of multi-stages, but experimentally, NOT one rocket has already had more speed than the maximum velocity of a bullet in airless tube.

In the air and at ground-level, the highest speed is 1.190km/hr .
High in the sky and only at the equator and only with a flight to the west, airplanes can get 2.860km/hr and nothing more, due to the rotation of the earth (40.000km in 24 hours = 1.666km/hr).
This is the reason why the Concorde is NOT supersonic from NY to Paris.

I will give all my money (and even my life) to the first person who knows a scientific publication, f.i. in PHYSICAL REVIEW, that contradicts the current 28.800km/hr-limit.

Spacetravel around earth needs 28.000km/hr

When you throw away a projectile, under an angle of 45 degrees, it will travel some distance before falling...So I asked myself...Is there a simple relation between the initial velocity and the realised distance?

Longest distance for a given initial velocity

 Velocity Distance 10 m/sec 10 meter (long jump) 20 m/sec 40 meter (discus) 30 m/sec 90 meter (javelin) 40 m/sec 160 meter (golf-ball) 80 m/sec 640 meter (bullet) 400 m/sec 16.000meter=16km (Max for real artillery) 800 m/sec 64 km (theoretical extrapolation) 8000m/sec=28.800km/hr 6.400 km (so it would fall behind the earth)

The higher the velocity, the further away the objects falls.
All experiments were done in the air,
so nothing had more velocity than 400m/sec, i.e. the velocity of the air-particles or the so-called sound-barrier.

On a height of 100 km, the gravitational acceleration is still 9.5m/sec/sec. For a circular orbit around the earth (r=6.400km), the velocity (v) must be 28.800km/hr or 17,500mph , because only then the centrifugal acceleration(vxv/r) can match the gravity. (calculate with g=10m/sec/sec)

I will give all my money (and even my life) to the first person who knows a scientific publication, f.i. in PHYSICAL REVIEW, that contradicts the 28.800km/hr-limit.

Conclusion : US-space-travel is FAKE

Since astron(a)uts, SCUD-missiles, rocket-bombs and TV-satellites weight more than ONE kilogram..., it is all religion and fake(lore),
done with real airplanes.

Since an airplanes can only fall 1 minute, without touching the ground, astron(a)uts can only be 'weightless' during that 1 minute in that (parabolic) fall.

I will give all my money (and even my life) to the first person who knows a scientific publication, f.i. in PHYSICAL REVIEW, that contradicts the (current) 28.800km/hr-limit.

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E-mail : mpeeters@freemail.nl