Check your work again. Consider using the 'y=mx+k' ('y=mx+b') form.

Question 1

Determine an equation of the line with slope 2, and a y intercept of 5.

 

x=5	y=5x+2	y=2x+5	y-5=2x
y/(x-5)=2	(y-5)/x=2	2x-y+5=0

Check your work again.  The 'y intercept' is not given.  Start back with your sketch.

Question 2

 

Determine an equation of the line with slope 3, and a x intercept of 2.

 

y=2x+3	y=3x+2	3x-y-6=0	y=3(x-2)
y/(x-2)=3	x/(y-2)=3

.

Question 3

 

Determine an equation of the line with slope -1, and the point (4,-3) is on the line.

 

y=-x+7	y=-x+1	x+y-1=0	4x-3y=-1
y+3=-(x-4)	(y+3)/(x-4)=-1	(y-3)/(x-4)=-1

Check your work again.  A perpendicular slope requires a 'negative reciprocal' of any given slope. The proceed with the format  y = mx + k  ( y = mx + b).
 

Question 4

Determine an equation of the line with a y intercept of 3, and a slope perpendicular to a line with slope = -0.5

 

y=2x+3	y=-0.5x+3	2x-y+3=0	(y-3)/x=2
y/(x-3)=2	y/(x-3)=-1/2

 
 

Question 5

Determine an equation of the line passing through (5,-4), and parallel to the y axis.

 

y=-4	x=5	y=5	x=-4
x-5=0	x+4=0

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