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Ferman's Cosmos Model Aq Atomic Quantity |
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Aq : “Quantity of atoms per unit of volume or weight”
The Atomic Quantity (Aq) or number of atoms per volume unit (litre) or per weight unit (Kg.) can be easily determined dividing the atomic quantity of water (Aqw) by the porosity coefficient (Pc). In volume Aq = Aqw /Pc In weight Aq = Aqw / (Pc x Density). Aqw = 33,5 x 10^24 Atoms/litre or kg. Volume: The atomic quantity of the water (Aqw) or quantity of oxygen atoms that contains the litre of water can be established in 33,5 x 10^24 atoms/litre. Therefore in simple molecules or materials the number of atoms for litres can be obtained easily. In the molecules and more complex materials we will obtain the total number of atoms firstly, and later we will readjust the quantity of atoms of each element keeping in mind the structure of this material. It is necessary to keep in mind (see porosity) that hydrogen doesn't count as number of atoms and therefore it is necessary to add to the total number of atoms the corresponding hydrogen atoms according to the molecule structure. This way for example in water that have 33,5 x 10^24 oxygen atoms for each litre, logically it have 67 x 10^24 atoms of hydrogen/litre. Adjustment examples: ---Quantity of atoms of: -- Gold in a litre (1 dm3) Aq = Aqw /Pc = 33,5 x 10^24 / 0,57 = 58.77 x 10^24 Atoms Gold/litre --Cesium 33,5 x 10^24 / 3,93 = 8,52 x 10^24 Atoms Cesium --Iridium 33,5 x 10^24 / 0,47 = 71,27 x 10^24 Atoms Iridium --Benzene 33,5 x 10^24 / 0,83 = 40,36 x 10^24 Atoms Carbon Plus 40,36 x 10^24 Atoms Hydrogen --Salt ClNa 33,5 x 10^24 / 0,75 = 44,66 x 10^24 Total atoms. 22,33 x 10^24 Atoms of Chlorine 22,33 x 10^24 Atoms of Sodium Weight The procedure is the same one, but in this formula the density of the element that we are measuring is also included. Example: ---Quantity of atoms of gold contained in a kg of the same one. Aq = Aqw / (Pc x Density). 33,5 x 10^24 : ( 0,57 x 19,3 ) = 3 x 10^24 |
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