If car A’s instantaneous velocity is greater than B’s instantaneous velocity, then that means that car A is moving faster than car B. Since acceleration is velocity x time, and since car A’s acceleration is bigger, car A will have more acceleration than care B.
5. The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in figure 2-13.
a) Identify the time intervals during which the velocity of the shuttle bus is constant.
b) Identify the time intervals during which the acceleration of the shuttle bus is constant.
everytime but 0s – 40s, 50s - 125s, 225s – 275s , where there is no acceleration.
c) Find the value for the average velocity of the shuttle bus during each time interval identified in b.
d) Find the acceleration of the shuttle bus during each time interval identified in b.
e) Identify the times at which the velocity of the shuttle bus is zero.
0s – 40s 225s – 275s
f) Identify the times at which the acceleration of the shuttle bus is zero.
0s – 40s, 50s - 125s, 225s – 275s
g) Explain what the shape of the graph reveals about the acceleration in each time interval.
When the line is strait, there is no acceleration. Whenever the line crosses or is on 0 m/s, the acceleration is 0. Whenever the line is not parallel to the x-axis, then there is acceleration.
6. Is the shuttle bus in item 5 always moving in the same direction? Explain, and refer to the time intervals shown on the graph.
No, the shuttle bus stops doesn’t move at 0s – 40s and 225s – 275s. All of the time after 275s, the bus is moving in the opposite direction than it was before. So from 275s to 600s the bus is moving in the opposite direction that if began with.