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Section 4.2: Multiplying Matrices Matrix addition is easy as pie (3.14 haha) to learn!!! You simply add together the corresponding numbers within the matrices together. For instance, for the following 2 matrices, you would add the numbers 8 and 10 together to get 18, and then add 3 and 3 beside them to get 6. When you add matrices, you are solving for one matrix. = You can multiply to matrices together if the number of columns in one is equivalent to the number or rows in the other. ex. a 4 by 2 matrix and a 2 by 3 matrix. The end product will yield one matrix that has a row number of 4 and a column number of 3. Since you had to have a column and row number being the same think of it this way: ( a 4 by 2 matrix meets a 2 by 3 matrix, = 4 x 2 2 x 4. If you imagine the 2's running away to getr married, they would leave the 4 and 3 alone to create their own matrix.) Multiplying the matrices will seem tricky at first, but once you get the hang of it, it becomes simple. You Try: 1) 4 x 6 * 6 x 3 =? 2) 3 x 4 * 4 x 7 =? 3) 15 x 23 * 15 x 24 =? Answers: 1) 4 x 3 2) 3 x 7 3) not possible. There isn't a row that is equal to the column. Multiplying Matrices Matrices can be multiplied together to get a new set of numbers. (a different matrix) Using the rule above (that only matrices with a like number of rows to columns can be multiplied together) we can multiply matrices. To find the entry in the first row and first column of AB, multiply corresponding entries in the first row of A and the first column of B. Then add (-1)(-3) + (3)(-4) = -9 = By continuing this pattern, you can obtain the following: = You Try: 1) Answers: 1) This situation would be useful in real life if say, you need to multiply 2 sets of numbers together, and find equivalent numbers for each. |
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4.1 Matrix Operations|4.2 Matrix Multiplication|4.3 Determinants 4.4 Identity and Inverse|4.5 Solving Systems Using Inverse Matrices |