Problem:
How can a chemical formula for Lead (II) Iodide be determined in the lab?
Procedure:
1. Mass out .42 grams of potassium iodide and dissolve in 25mL of water in a very clean beaker.
2. Using tape label this beaker iodide ions.
3. Mass out .42 g of lead nitrate and dissolve in 25mL of water in a very clean beaker.
4. Label this beaker lead ions.
5. Measure out 25mL pure water and place in a very clean beaker.
6. Label this beaker distilled water.
7. Using the above stock solutions fill in data chart.
Picture:
Draw a diagram of your lab set up and label all parts
Chemical Reaction:
lead nitrate + potassium iodide ---------> lead iodide + potassium nitrate
Data Chart:
Test Tube Lead Ions Iodide Ions Water Formula Rank
#1 4mL 2mL 4mL Pb2I
#2 2mL 4mL 4mL PbI2
Safety Notes:
1. Wear apron
2.Wear safety goggles
Conclusion:
1. Which test tube produced the most precipitate?
2. What is the correct formula for lead idodide?