Bisecting Segments and Angles

Section 1.7

 

 

 

   Two objects are said to be congruent if they have the same size and shape.

 

  The midpoint of a segment is the point that divides the segment into two congruent segments.

 


  If M is the midpoint of   XY ,  then

                   XM  = MY   and   XM    MY

                   XM  = ½ XY   and   MY  =  ½ XY

 

 

 

 

 

 

 

  A bisector of a segment is a line, segment, ray or plane that intersects the segment at its midpoint. 

 

 


   Plane E bisects  RT

 

 

 

 

 


  MN  bisects  XY , but

 


       XY does not bisect MN

 

 


   CD bisects  EF   and

 


EB bisects CE

 


G is the midpoint of  CE and EB

 

 

  Solving Two Step Equation Review   (see Toolbox page 696)

 

              3x  + 9 = 15

     3x  +  9    9  =  15 – 9

                     3x  =  6

                    3x  =  6

3                 3

x  =  2

 

 

 

 

 


  MN  bisects  XY

 

Find the value of n

Y

 
 


If MN  bisects  XY, then

         XA  =  AY   ,  then

      4n – 6 = 26        (now solve for n)

4n – 6 + 6 = 26 + 6

          4n   =  32

          4n   =  32

          4           4
           n    =  8

 

 

   Coordinates

 

A pair of numbers used to locate a point on a coordinate plane; the first number tells how far to move horizontally and the second number tells how far to move vertically

Example:

(1,2) represents 1 unit to the right of zero and 2 units up.

 

 

What are the coordinates of C?

 

What is the distance form B to C?

 

What is the coordinate of the midpoint of BC?

 
Example:

(1,3) are the coordinates of A.
(-4,-3) are the coordinates of B.

 

Source:  http://www.harcourtschool.com/glossary/math2/index6.html

 

 

 

 

 

 

  A bisector of an angle is a ray or line that divides the angle into two congruent angles.

 

 

  The (interior) bisector of an angle is the line or line segment which cuts it into two equal angles on the same "side" as the angle.

Source: http://mathworld.wolfram.com/AngleBisector.html

 

 


    If EC bisects     BED, then:

 

·                  m        BEC  =  m       CED

·                           BEC            CED

·                  m      BEC = ½ m        BED 

·                  m      CED = ½ m        BED  

 

 

 

 


   EC bisects      BED

Find the value of x and the m        DEC

 


If  EC bisects      BED  then

 

              m        DEC  =  m         BEC

                        2x –3  =  5x – 15

                 2x – 2x – 3  =  5x – 2x  – 15

       3 = 3x – 15

                       – 3 + 15 = 3x – 15 + 15
                             12 = 3x

                             12 = 3x

                              3       3
                              4 = x

 

   If x = 4 and the m        DEC = 5x – 15 ,  substitute 4 for x in 5x – 15

 

                   5x – 15

                   5 (4) – 15 =
                     20 –15   =

                          5o