Solid: Cube
Cut: Edge
Sequence: B
Term: 1
| Name | Number | Colors | Permutation | Orientation | Orbits |
| Corner | 8 | 3 | Odd | 3, Fixed | 1 |
| Edge | 12 | 2 | Even | 2, Free | 1 |
| Wing | 48 | 1 | Even | N/A | 2, Chirality |
| Face | 24 | 1 | Odd | N/A | 1 |
| Center | 6 | 1 | Odd | N/A | 1 |
Slice Summary
| Cut Type | Layer | Period | Pieces Affected | Total Parity |
| Edge | 1 | 2 |
1. 1 Corner Swap 2. 2 Edge Swaps 3. 1 Edge Flip 4. 8 Wing Swaps 5. 3 Face Swaps 6. 1 Center Swap |
Odd |
Method 1
This method solves the puzzle one piece type at a time. Various intuitive step 1-3 combinations fail because of the parity condition, which is quite difficult to deal with in non-by-piece-type methods. It turns out that in this case a by-piece-type method is probably quite efficient, compared to waht's possible. Unfortunately this si also quite boring.
Step 1 - Solve Corners
The corners behave the same way on Cubes EA, EAB, EB, EBC, EC, and ECD.
Twist two corners: UF UR UB UL UB UR
Twist three corners: (UF UR UB UL) x 3
Step 2 - Solve Centers
Now solve the centers. At this point the parity is quite easy to fix; it works by swapping all pieces around the two problem centers. This is because it is an even permutation to swap the 8 corners and 4 centers which have been solved at this point (6 swaps).
Three cycle centers: UR UL UR UL
Swap two centers: FR BL (UF DR FR DR UF) (UR DF FR FD UR)
Step 3 - Solve Faces
The faces are the four one-color pieces adjacent to each center. Solve as many with the two-swap as possible early on; generally after a while the three cycle is needed for furter progress.
Swap two pairs of faces: (UF UR) x 3
Three cycle faces: (UF UR) x 3 DR (UF UR) x 3 DR
Step 4 - Solve Edges
Solve the edges in this step, using a four-move three-cycle and setup moves. Use setup moves to correctly twist as many edges as possible during this step to save moves on correcting flipped edges later.
Three cycle edges: UR FL UR FL
Flip two edges: UF (UR FL UR FL) UF (FL UR FL UR)
Step 5 - Solve Wings
Finish the puzzle by solving the wings, using a simple three-cycle. Keep in mind that there are two orbits of wings, due to chirality. Two slightly different three-cycles are provided, the first cycles two of the pieces in the same face so it is easier to use, the other cycles three pieces from three different faces, so there is a higher chance of having more efficient three-cycles.
Three cycle wings: (UR FL UR FL) (UB BR UB) (FL UR FL UR) (UB BR UB)
Three cycle wings: (FL UR FL UR) (UB FR UB) (UR FL UR FL) (UB BR UB)