Solid: Cube
Cut 1: Vertex
Sequence: B
Term: 1
| Name | Number | Colors | Permutation | Orientation | Orbits |
| Edge | 12 | 2 | Even | None | 1 |
Slice Summary
| Cut Type | Layer | Period | Pieces Affected | Total Parity |
| Vertex | 1 | 3 | 1. 1 Edge Three Cycle | Even |
Method Overview
This page will describe two systematic ways one could go about solving this puzzle. For any particular solve, the solver should choose which one will yield the best result. Also, in each step the solver should look for ways to shorten the succeeding steps. Ultimately, the quickest or shortest way to solve this puzzle is wholistically; this will occur when all three steps become totally blended together.
Method 1
The method works by solving the puzzle with a down-up approach.
Step 1 - Solve four Edges of one face
Solve four edges which all contain a common color. If necessary, use other edges to determine which colors belong on opposite faces. As long as the correct colors are opposite each other the rest of the solve will be fine because this puzzles has two valid solved color schemes. Preferably this step should be 1-2 moves. If it needs to be 3 moves or more, look at method 2.
Step 2 - Solve four edges around the equator
Solve the four "vertically aligned" edges; that is, those which belong around the middle of the puzzle.
Step 3 - Solve four Edges of top face
Finish the top edges using a simple three-cycle. Often one piece will be solved so only one three-cycle will be needed.
Method 2
This method solves the puzzle from one corner to the other; this takes advantage of the nature of the puzzle by solving the last three pieces in one twist.
Step 1 - Solve three Edges around one corner
Quickly and easily establish a color scheme by solving three edges around one corner.
Step 2 - Solve the six Middle Edges
Solve the six pieces between the step 1 corner and the corner opposite it. Use the step 1 corner to deduce the color scheme.
Step 3 - Finish last corner
Since the pieces of this puzzle can only be in an even permutation and they are not flippable, once there are only three pieces left around one corner they will be able to be solved in at least one twist.