E-9

Pre-lab exercises

  1. The buoyant force experienced by the solid is W2 - W3
    V = W/r, (W2 - W3)/r = Vf
    V = Vf, hence W/r = (W2 - W3)/rf. we have
    r = rf[W/(W2 - W3)]
  2. The density of the alloy is r = m/V, m = m1 + m2
    The volumes of the two metals are V1 and V2 respectively.
    V1 = m1/r1, and V2 = m2/r2.
    r = (m1 + m2)/(V1 + V2) = (m1 + m2)/(m1/r1 + m2/r2)
  3. The specifiiic gravity is unitless

Calculation

7. Use modified equation (9-3): rf = [r(W - Wapp)]/W

Error Analysis

4. The expression can be derived as
r = rfW/(W - Wapp) = rfW(W - Wapp)-1
sr2/r2 = sW2/W2 + s(W-Wapp)2/(W - Wapp)2.
By using eq Z = ax + by + cz, we can estimate
s(W- Wapp)2 = sW2 + sWapp2,
since W and Wapp are both measured with the same balance, their uncertainties, sW are the same.
sr2/r2 = sW2/W2 +2sW2/(W - Wapp)2
= sW2[(W - Wapp)2 + 2W2]/W2(W- Wapp)2 = sW2(W2 - 2WWapp + Wapp2 + 2W2)/W2(W - Wapp)2
taking approximation 2WWapp » 2W2 and r = rfW/(W - Wapp), we have
sr2 = rf2(W2 + Wapp2)sW2/(W - Wapp)4

Answer to the question 1
In step 1, 2 we use r = m/V, where V = pa2L, but in step 3, 4 we use r = rfW/(W - Wapp), now you try to derive sr in two different equations similar to the derivation that I did in Error analysis 4, then compare the results. You can tell which methode is more precise. This is a very interesting problem.

 
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