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We assume that the IP address of 219.17.102.0 is reserved for the core WAN topology. Each of the 3 Regional Hubs has 4 serial ports connections to each other by 4 T1. For each connection, a pair of IP addresses are needed for the connected ports. So in order for the calculation this will be: 3 x 4 pairs = 24 IP addresses are needed for the 3 routers. Assume that the IP 219.17.102.0 is subnetted by borrowing 6 bits, so each subnet consists of 4 IP (2 bit host portion), in which only 2 IP usable. So we have the IP ranges from subnet 219.17.102.4, 219.17.102.8, and so on with the subnet 255.255.255.252:
IP Address Scheme:
|
From |
To |
Router Data Center to Router Service Center |
S0: 219.17.102.5 |
S0 - 219.17.102.6 |
S1: 219.17.102.9 |
S1 - 219.17.102.10 |
|
S2: 219.17.102.13 |
S2 - 219.17.102.14 |
|
S3: 219.17.102.17 |
S3 - 219.17.102.18 |
|
|
|
|
Router Data Center to Router Shaw Butte |
S4: 219.17.102.21 |
S0 - 219.17.102.22 |
S5: 219.17.102.25 |
S1 - 219.17.102.26 |
|
S6: 219.17.102.29 |
S2 - 219.17.102.30 |
|
S7: 219.17.102.33 |
S3 - 219.17.102.34 |
|
|
|
|
Router Shaw Butte to Router Service Center |
S4: 219.17.102.37 |
S4 - 219.17.102.38 |
S5: 219.17.102.41 |
S5 - 219.17.102.42 |
|
S6: 219.17.102.45 |
S6 - 219.17.102.46 |
|
S7: 219.17.102.49 |
S7 - 219.17.102.50 |
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