Mathematics
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   Grade 7: Patterning and Algebra  | 
  
   Planning: Term # Tracking: Ach. Level  | 
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   Overall Expectations  | 
  
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  represent linear growing patterns (where the terms are whole numbers) using
  concrete materials, graphs, and algebraic expressions;  | 
  
   
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  model real-life linear relationships graphically and algebraically, and solve
  simple algebraic equations using a variety of strategies, including
  inspection and guess and check.  | 
  
   
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   Specific Expectations  | 
  
   
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  Patterns and Relationships
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  represent linear growing patterns, using a variety of tools (e.g., concrete
  materials, paper and pencil, calculators, spreadsheets) and strategies (e.g.,
  make a table of values using the term number and the term; plot the
  coordinates on a graph; write a pattern rule using words);  | 
  
   
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  make predictions about linear growing patterns, through investigation with
  concrete materials (Sample problem: Investigate the surface area of towers
  made from a single column of connecting cubes, and predict the surface area
  of a tower that is 50 cubes high. Explain your reasoning.);  | 
  
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  develop and represent the general term of a linear growing pattern, using
  algebraic expressions involving one operation (e.g., the general term for the
  sequence 4, 5, 6, 7, … can be written algebraically as n + 3, where n
  represents the term number; the general term for the sequence 5, 10, 15, 20,
  … can be written algebraically as 5n, where n represents the term number);  | 
  
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  compare pattern rules that generate a pattern by adding or subtracting a
  constant, or multiplying or dividing by a constant, to get the next term
  (e.g., for 1, 3, 5, 7, 9, …, the pattern rule is “start at 1 and add 2 to
  each term to get the next term”) with pattern rules that use the term number
  to describe the general term (e.g., for 1, 3, 5, 7, 9, …, the pattern rule is
  “double the term number and subtract 1”, which can be written algebraically
  as 2 x n – 1) (Sample problem: For the pattern 1, 3, 5, 7, 9,…, investigate and
  compare different ways of finding the 50th term.).  | 
  
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  Variables, Expressions and Equations
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  model real-life relationships involving constant rates where the initial
  condition starts at 0 (e.g., speed, heart rate, billing rate), through
  investigation using tables of values and graphs (Sample problem: Create a
  table of values and graph the relationship between distance and time for a
  car travelling at a constant speed of 40 km/h. At that speed, how far would the
  car travel in 3.5 h? How many hours would it take to travel 220 km?);  | 
  
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  model real-life relationships involving constant rates (e.g., speed, heart
  rate, billing rate), using algebraic equations with variables to represent
  the changing quantities in the relationship (e.g., the equation p = 4t
  represents the relationship between the total number of people that can be
  seated (p) and the number of tables (t), given that each table can seat 4
  people [4 people per table is the constant rate]);  | 
  
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  translate phrases describing simple mathematical relationships into algebraic
  expressions (e.g., one more than three times a number can be written
  algebraically as 1 + 3x or 3x + 1), using concrete materials (e.g., algebra
  tiles, pattern blocks, counters);  | 
  
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  evaluate algebraic expressions by substituting natural numbers for the
  variables;  | 
  
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  make connections between evaluating algebraic expressions and determining the
  term in a pattern using the general term (e.g., for 3, 5, 7, 9, …, the
  general term is the algebraic expression 2n + 1; evaluating this expression
  when n = 12 tells you that the 12th term is 2(12) + 1, which equals 25);  | 
  
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  solve linear equations of the form ax = c or c = ax and ax + b = c or
  variations such as b + ax = c and c = bx + a (where a, b, and c are natural
  numbers) by modelling with concrete materials, by inspection, or by guess and
  check, with and without the aid of a calculator (e.g., I solved x + 7 = 15
  by using guess and check. First I tried 6 for x. Since I knew that 6 plus 7
  equals 13 and 13, is less than 15, then I knew that x must be greater than
  6.”).  | 
  
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   Student Name:  | 
  
   
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Expectations: Copyright The Queen's Printer for Ontario, 2005. Format: Copyright B.Phillips, 1998.