General Chemistry 111 Lab Report # 1
Measuring Densities of Wood Samples
Dr. Anthony L Dent
Abstract (25%)
In one paragraph, tell: a) What was done, b) How it was done, c) what the significant results were. You may add a concluding sentence to explain any unexpected results. Prefer to receive typed reports, but LEGIBLELY hand written are acceptable. Reports are due one week after the conclusions of the lab work.
Introduction/Objectives/Theories to be Explored (10%)
What was the purpose of this work? What was it expected to demonstrate? Do you expect that it will achieve its objectives? In other words explain why you did the work in the first place. Because it was assigned is a failing response!
Experimental procedures (10%)
In the paragraph, give the steps involved in obtaining the experimental results. For example, tell how you measured the bulk density of a sample.
Experimental Results (30%)
Provide a table of the experimental data and any calculated results. For example:
Table 1. Data for Density Determinations for Three Types of Wood Samples. |
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| Samples | CEDAR |
Pine |
Pressure Treated Pine |
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| C - x | C - y | S - z | P - x | P - y | P - z | T - 26 | T - y | T - z | |
| Total weight | 165.0 g | ||||||||
| Length, cm | 12.0 cm | ||||||||
| Width, cm | 7.5 cm | ||||||||
| Thickness, cm | 3.8 cm | ||||||||
| Total Volume | 342.0 cm3 | ||||||||
| Weight soaked | 174.0 g | ||||||||
| Weight water | 9.0 g | ||||||||
| Water Volume | 9.0 cm3 | ||||||||
| True Volume | 333 0 cm3 | ||||||||
| True Density | 0.495 g/ cm3 | ||||||||
| Average TD | X |
X |
X |
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Graphical display of data (where warranted to show dramatic differences or unique similarities). Sometimes, a picture is worth a thousand words, sometimes not.
Summary/Conclusions (15%)
Explain your results. Was there anything unexpected? Are there any generalities that can be concluded?
Appendix (10%)
Show sample calculations here for your data summarized in tables reported above.
EXAMPLES of Sample calculations for PT-26
a)
Total Volume (measured) of PT - 26 = 12.0 cm x 7.5 cm x 3.8 cm = 342.0 cm3Apparent density = mass (PT-26)/ Total Volume = 165.0 g / 342.0 cm3 = 0.482 g/cm3
Water Volume = [Weight soaked, g - Total Weight, g] / 0.998 g/cm3 = [174.0 g - 165.0 g]/ 998 g/cm3
= 9.0 cm3
True Volume = Total Volume - Water Volume = 342.0 cm3 - 9.0 cm3 = 333 cm3
True Density = mass (PT-26)/ True Volume = 165.0 g / 333.0 cm3 = 0.495 g/cm3