


(b) To determine the number of turns a rolling circle with radius R makes as it rolls around a fixed circle with radius F, we think of unrolling the fixed circle (as if it were a hooly hoop) on a flat surface, which would have length of 2 pi F.

Hence, if we roll the outside circle of radius R (circumference 2 pi R) on this line, the number of turns it will make will be
But, the rolling circle in our problem does not roll along a line, but around a circle and hence the number of rotations the rolling circle makes as it rolls around a fixed circle of radius F is one more than F/R, or
You can see this by imagining sliding the outside circle around the fixed circle (keeping the same point of the sliding circle in contact with the fixed circle), and noting it rotates once as a result of going around the circle. The following table gives the number of turns for different values of R and F.
| R/F | 1 | 2 | 3 | 4
| 1 | 2 | 3 | 4 | 5
| 2 | 1 1/2 | 2 | 2 1/2 | 3
| 3 | 1 1/3 | 1 2/3 | 2 | 2 1/3
| 4 | 1 1/4 | 1 1/2 | 1 3/4 | 2
| |
For example, if the radius of the fixed circle was F = 3 inches, and the radius of the rolling circle was R = 4 inches, then the rolling circle would undergo T = 1 3/4 turns as it rolled around the fixed circle.
It is interesting to note that if the rolling circle were inside the fixed circle as shown in the picture below, then (by a similar argument) the number of rotations of the rolling circle will be R/F - 1. In this case, if we slide the inside circle counterclockwise inside the outer fixed circle, keeing the same point of the inner circle in contact with the outer circle, then the rotation of the inner circle is clockwise, but when we roll the inner circle counterclockwise inside the outer circle, the rotation is clockwise, and hence we subtract 1 from F/R instead of adding it.

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Last modified on Wednesday, March 17, 1999