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# findall2 - Finds all regex matches in a string, for each match return 
# the matched string and the start character of the match. 
# (Returns a list of tuples: (match,start))
# (Python's findall extended to returns start position also) 
#=============================================================================
import re, sys

def findall2(pattern,string):
    regex = re.compile(pattern,re.IGNORECASE | re.DOTALL)
    pos = 0
    matched = regex.search(text,pos)
    matches = []
    while matched:
          groups = matched.groups()
          value  = groups[0]
          start  = matched.start()
          pos    = matched.end() + 1
          tuple = (value,start)
          matches.append(tuple)
          matched = regex.search(text,pos)
    return matches

#----------------------------------------------------------------------
# main program:

if __name__ == "__main__":
   if len(sys.argv) != 3:
      text = "Once upon a time, far off in a land of fairies and goblins there lived a very cruel goblin, this goblin had a particularly ugly wart on the end of his nose..."
      #                                                                                                           1111111111111111111111111111111111111111111111111111111111111      
      #                 1111111111222222222233333333334444444444555555555566666666667777777777888888888899999999990000000000111111111122222222223333333333444444444455555555556
      #       01234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890 
      pattern = "(goblin)"
      matches = findall2(pattern,text) 
      print matches
      #print "Usage: ", sys.argv[0], "pattern string"
   else:
      pattern = sys.argv[1]
      string  = sys.argv[2]
      matches = findall2(pattern,string) 
      print matches