Math Jewels
By: JulieOn this page, I will explain how to solve a Linear Equation, solve Literal Equations, and write an equation of a line.
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Linear Equations
x+4= 9 write the problem -4 -4 isolate the variable by subtracting four from both sides x = 5 the answer is x = the answer
6x-4 = 2x+10 problem +4 +4 isolate variable by adding 4 to both sides 6x = 2x+14 new problem -2x -2x isolate the number so that if is variable = number 4x = 14
4 4rid the x of the number: divide by 4 on both sides x = 3.5 answer
2(x+6) = -2(x-4) problem 2x+12 = -2x+8 distribute the 2 and -2 through the problem using distributive property -12 -12 isolate the variable: subtract 12 2x = -2x-4 new problem +2x +2x isolate the number: add 2x 4x = -4
4 4isolate the variable: divide by 4 x = -1 answer
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Literal Equations
4x+8y = 17; solve for y problem -4x -4x isolate the variable that is to be solved by subtracting 4x 8y = -4x+17
8 8 8isolate the variable that is to be solved by dividing by 8 y = -1/2 x + 17/8 answer
E = IR ; solve for I
R R- Problem
- isolate the variable to be solved: divide by RI = E
Ranswer
F = G Mp x R ; solve for G
x R R- problem
- rid the problem of the denominator of the fraction: multiple both sides by RFR = G Mp
Mp Mpisolate the variable by dividing by Mp G = FR
Mpanswer The Equation of the Line
Slope-intercept form: y = mx+b
- m = the slope
- b = y-interceptPoint-slope form: y-y1 = m(x-x1)
- m = slope
- (x1-y1) is the point on the lineStandard form: ax+by = c
- a, b, c = numbers
- ax = the slope
- by = the answer of slope intercept after distribution
- c = the y-intercept- All forms will be found for each problem.
point: (-6, 5), m=3 problem y-5 = 3(x+6) substitute points and slope into point-slope form y-5 = 3x+18
+5 +5- distribute using distributive property
- isolate y by adding 5y = 3x+23 slope intercept form -3x -3x to get to standard from: x andy have to be on the same side - so, subtract 3x from both sides -3x+y = 23 there can be no negative or fractions in the front of standard form:so, multiply all numbers by -1 3x-y = -23 standard form
find the equation of the line that passes through (8,5),(11,14) problem 14-5 = 9 = 3
11-8 3find the slope by substituting into the slope formula: y1-y2
x1-x2y-5 = 3(x-8) substitute into point-slope form y-5 = 3x-24
+5 +5- distribute
- isolate the yy = 3x-19 slope-intercept form -3x -3x put the x and y together form standard form -3x+y = -19 no negatives or fractions in front: multiply by -1 3x-y = 19 standard form
find the equation of the line for (1,-1) and is perpendicular to line y = -(1/2)x+6 -problem
- to find the slope of the perpendicular line, flip the slope and multiply by -1y+1 = 2(x-1) point-slope form y+1 = 2x-2
-1 -1- distribute
- isolate the yy = 2x-3 slope-intercept form -2x -2x put the x and y on the same side -2x+y = -3 no negative of fraction in front 2x-y = 3 standard form Check out these other nifty sites!
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