Math Jewels
                                                                By: Julie

  On this page, I will explain how to solve a Linear Equation, solve Literal Equations, and write an equation of a line.

Linear Equations
 
x+4= 9 write the problem
  -4  -4 isolate the variable by subtracting four from both sides
   x = 5 the answer is x = the answer

 
6x-4 = 2x+10 problem
   +4       +4 isolate variable by adding 4 to both sides
 6x = 2x+14 new problem
-2x   -2x isolate the number so that if is variable = number
4x = 14
4       4
rid the x of the number: divide by 4 on both sides
x = 3.5 answer

 
2(x+6) = -2(x-4) problem
2x+12 = -2x+8  distribute the 2 and -2 through the problem using distributive property
     -12         -12 isolate the variable: subtract 12
 2x = -2x-4 new problem
+2x  +2x  isolate the number: add 2x
4x = -4
 4     4
isolate the variable: divide by 4
x = -1 answer

Literal Equations
 
 
 4x+8y = 17; solve for y  problem
-4x         -4x isolate the variable that is to be solved by subtracting 4x
8y = -4x+17
 8      8   8
isolate the variable that is to be solved by dividing by 8 
y = -1/2 x + 17/8 answer

 
E = IR ; solve for I
R    R
- Problem
- isolate the variable to be solved: divide by R
I = E
     R
answer

 
  F = G Mp x R    ; solve for G
x R         R
- problem
- rid the problem of the denominator of the fraction: multiple both sides by R
FR = G Mp
Mp     Mp
isolate the variable by dividing by Mp
G = FR
      Mp
answer

The Equation of the Line

Slope-intercept form:  y = mx+b
        - m = the slope
        - b = y-intercept

Point-slope form:  y-y1 = m(x-x1)
         - m = slope
        - (x1-y1) is the point on the line

Standard form: ax+by = c
         - a, b, c = numbers
         - ax = the slope
         - by = the answer of slope intercept after distribution
         - c = the y-intercept

- All forms will be found for each problem.
 
 
point: (-6, 5), m=3 problem
y-5 = 3(x+6) substitute points and slope into point-slope form
y-5 = 3x+18
 +5       +5
- distribute using distributive property 
- isolate y by adding 5
  y = 3x+23 slope intercept form
-3x    -3x to get to standard from: x andy have to be on the same side - so, subtract 3x from both sides 
-3x+y = 23 there can be no negative or fractions in the front of standard form:so, multiply all numbers by -1
3x-y = -23 standard form

 
find the equation of the line that passes through (8,5),(11,14) problem
14-5 = 9 = 3
11-8    3
find the slope by substituting into  the slope formula: y1-y2
                           x1-x
y-5 = 3(x-8) substitute into point-slope form
y-5 = 3x-24
 +5    +5
- distribute
- isolate the y 
 y = 3x-19 slope-intercept form
-3x   -3x put the x and y together form standard form
-3x+y = -19 no negatives or fractions in front: multiply by -1
3x-y = 19 standard form

 
find the equation of the line for (1,-1) and is perpendicular to line    y = -(1/2)x+6 -problem
- to find the slope of the perpendicular line, flip the slope and multiply by -1
y+1 = 2(x-1) point-slope form
y+1 = 2x-2
  -1    -1
- distribute
- isolate the y
  y = 2x-3 slope-intercept form
-2x -2x put the x and y on the same side
-2x+y = -3 no negative of fraction in front
2x-y = 3 standard form

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