Problem: y = 5 - 4x
3x - 2y =12 2. 3x - 2(5 - 4x) = 12 |
Look at the problem. Make one of
the
equations equal to one of the varables. Next take the problem following the varable that is alone and substitute it for the same varable in the other problem. |
3. 3x - 10 + 8x = 12
|
Next work the problem out to fin
x.
Next put answer to x in place of x in the problem that equals y. This will give you the answer to y. Then put it in (x,y). |
1. x + y = 9
2x - y = -3 2. 3x = 6 3. 3x/3 = 6/3 4. x = 2 5. 2 + y = 9 6. 2 + y = 9 -2 -2 y = 7 7. (2,7) |
1. You look at the problem and
see if you are going to need multiply either of the problems to make one
varable cancle.
2.Add the problems together. 3.This should give you a lone varable and a constant. 4.Find the answer to a varable's value. 5.Next substitute it in it's place in one of the problem's. 6.Find the other varable's value. 7.Put it in (x,y) |
1.One day a store sold 45 pens,
one kind at $8.50 and another kind at $9.75. In all $398.75 was taken in.How
many of each kind were sold.
2.Find the first equations. X +
Y = 45
|
X + Y = 45
y = -x + 45 8.5x + 9.75y = 398.75 8.5x + 9.75(-x + 45) = 398.75 8.5x - 9.75x + 438.75 = 398.75 -1.25x + 438.75 = 398.75 -438.75 -438.75 -1.25x = -40 x = 32 32 + y = 45 -32 -32 y = 13 |