歸約公式

此方法為站長在計算根為α6666的方程的系數時發現的。

設[α,β,γ,σ,......,δ,μ,φ,ν]有w個根
αnnnn+......+δnnnn =

(n-1)(n-1)(n-1)(n-1)+......+δ(n-1)(n-1)(n-1)(n-1)][α+β+γ+σ+......+δ+μ+φ+ν]

-

(n-2)(n-2)(n-2)(n-2)+......+δ(n-2)(n-2)(n-2)(n-2)][αβ+αγ+ασ+......+αδ+αμ+αφ+αν+......+φν]

+

(n-3)(n-3)(n-3)(n-3)+......+δ(n-3)(n-3)(n-3)(n-3)][αβγ+αβσ+......+αβδ+αβμ+αβφ+αβν+......+μφν]

-

(n-4)(n-4)(n-4)(n-4)+......+δ(n-4)(n-4)(n-4)(n-4)][......]

+

(n-5)(n-5)(n-5)(n-5)+......+δ(n-5)(n-5)(n-5)(n-5)][......]

-

(n-6)(n-6)(n-6)(n-6)+......+δ(n-6)(n-6)(n-6)(n-6)][......]

+

(n-7)(n-7)(n-7)(n-7)+......+δ(n-7)(n-7)(n-7)(n-7)][......]

-

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±

(n-w)(n-w)(n-w)(n-w)+......+δ(n-w)(n-w)(n-w)(n-w)][αβγσ......δμφν]