Integral of f-g(dx) from 0 to 1 = the integral of (2x(1-x)) - 3(x-1) (square root of x)(dx)
b. Find the volume of the solid generated when the shaded region enclosed by the graphs of f and g is revolved about the horizontal line y=2.
Pi(integral of ((2-f)squared)dx - pi integral of (2-f)squared dx
c. Let h be the function given..........blah blah blah etc etc etc........could be used to find the value of k.
Integral of (Adx) = integral of (f-g)squared dx=15