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10a) Solve the radical equation SOLUTION To solve the equation for It does not matter which one. To be specific, isolate so Square both sides of the equation to get rid of the square root on the left side Multiply out the right side of the equation by using the identity Square of a Difference You can identity Remember that if you can not identify the terms in your problem so that your problem looks exactly like the identity you want to use, then you can not use the identity. You have to try to find another identity that you can try to use to work out your problem. or You still have a square root in the equation, so you repeat the process and isolate Subtract or To further clean up the equation, divide both sides of the equation by To get rid of the square root on the right side, again square both sides of the equation Finally, to get so Tentative, because you have to check whether Substitute Then, is The left side is so you have the relationship So 10b) Solve the radical equation SOLUTION In form this problem is exactly like problem 10a). Following the same steps, isolate one of the square roots Square both sides of the equation to get ride of the square root on the left side of the equation To work out the square on the right side of the equation, use the identity Square of a Sum where so or To isolate the square root remaining on the right side, subtract sides of the equation or To further simplify the equation, divide both side of the equation by Now, again, you square both sides of the equation to get rid of the square root on the right side The left side you work out using the identity Square of a Difference where This is a quadratic equation, so put it in standard form. To get on both sides of the equation subtract or This equation can not be factored easily, so you use the quadratic formula to solve it. Remember that the solutions to a quadratic equation in standard form are given by the quadratic formula For your equation Substituting these values into the quadratic formula, you get ![]() or So the tentative solutions are You say "tentative", because you must check whether these numbers actually are solutions of the original equation Testing these two numbers, you will find that is a solution of the original equation. 11) Solve the rational equation SOLUTION The method for solving rational, or fractional, equations is to multiply the equation by the lowest common denominator (LCD) of all the fractions in the equation. First, you must factor all the denominators. Here, the denominators are so the LCD is You multiply both sides of the equation by the LCD in order to get rid of all the fractions in the equation. The factors common in the LCD and in the denominators all cancel, so the equation is cleared of all the fractions. Canceling the common factors, you get Using the Distributive Law to do the multiplications, you get Combining like terms , writing the highest power of the equation in standard form with the 0 on one side, you get Multiply the equation by To solve this equation of the third degree, you factor the left side by grouping or Factoring more, using the identity Difference of Two Squares you get The solution is now just a few seconds away! Using the Zero Products Principle, you set each linear factor in the product equal to solve and solve each linear equation Remember, when you solve rational equations, these numbers are tentative solutions. You have to check whether they are solutions of the original, rational equation. You check by substituting each number back into the original, fractional equation to see whether it works or not. The original, fractional equation is If you put an undefined operation. So If you put in Is this equation true? To find out, you do more arithmetic on the left of the equation The LCD is equivalent fractions with or or because the left side of the equation is now the same as the right side of the equation. So 12) Simplify the complex fraction SOLUTION Using the definition of negative exponents as reciprocals, re-write the fraction ![]() Simplify this complex fraction by multiplying the numerator (the top) and the denominator (the bottom) of the complex fraction by the LCD of the constituent fractions. Here so, do the multiply ![]() Powers of ![]() To see if the fraction can be simplified further, factor the numerator and the denominator. Remember the identity for the Sum of Two Cubes So ![]() The is
the final answer.
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