Ramp Lab Questions

  1. v1 = 12.5 m/s
    v2 = 22.5 m/s

    2. t = 7.5 s
    a = ? m/s2
    formula a = (v2 - v1)/t
    substitute a = (22.5 - 12.5)/7.5
    solve a = 1.33 m/s2
    Statement: The acceleration is 1.33 m/s2

  2. v1 = 13.5 m/s
    t = 4.2 s
    v2 = 0.0 m/s That what comes to rest means.
    a = ? m/s2
    formula a = (v2 - v1)/t
    substitute a = (0 - 13.5)/4.2
    solve a = -3.214 m/s2 Statement: the soccer ball slows down at a rate of 3.21 m/s2

  3. v1 = 13.5 m/s
    v2 = 0.0 m/s
    formula vave = (v1 + v2)/2
    substitute vave = (0 + 13.5)/2
    solve vave = 6.75
    Statement: The average veleocity is 6.75 m/s

    To find the distance, two ways
    a) vave = 6.75 m/s
    t = 4.2 s
    d = ? m
    formula d = vave x t
    substitute d = 6.75 x 4.2
    solve d = 28.35
    Statement: the ball rolls 28.4 m then stops.

    b) You could use the formula v22 = v12 + 2ad
    substitute 0.02 = 13.52 + 2(-3.214)d
    solve d = -182.25/(2 x -3.214)
    d = 28.35 Statement: v12

  4. d = 150 m
    t = 4.75 s
    vave = ? m/s
    formula vave = d/t
    substitute vave = 150/4.75
    solve vave = 31.6 m/s
    Statement The speed of the ball is 31.6 m/s
    This is not the speed of the ball at the end of the ramp beacuse it is only the average of the final speed and the initial speed.
    The final speed would be found by using the formula
    vave = (v1 + v2)/2
    substitution 31.6 = (0.0 - v2)/2
    solving v2 = 31.6 x 2 = 63.2 m/s
    The speed of the ball at the end of the ramp is 63.2 m/s