Stopping
Distance And Time
The
Math Is Simple
After
reading the TIP entitled You
Only Hit The Car If You Don't Quite Stop In Time a person sent me
a gentle critique of it as follows:
The
general points you make are fine but I think you might want to check
your math..
Traffic
Engineers have some rules-of-thumb they developed over time. They,
for example, have found that if the street surface is dry, the
average person can safely decelerate an automobile at the rate of
15 feet per second (fps). That is, an average person can slow down
at this rate without any real likelyhood that they will loose
control in the process.
The
measure of velocity is distance divided by time (fps). The measure
of acceleration (or deceleration in this case) is feet/sec/sec in
the units you chose.
I
believe he was trying to be helpful and was not just taking shots.
As to
the measure of deceleration being fpsps rather than fps, I take no
issue with that. My article said that you could '... decelerate .. at
the rate of 15 fps' , but I think it is clear from the context that
what I was saying was that regardless of the velocity, say it starts
at 88 fps, you could scrub off 15 fps every second. ie, after 1 second
your velocity would be 73 fps, after 2 seconds it would be 58 fps,
etc. For the mathematically inclined it would have been more accurate
to say 'fpsps' rather than 'fps', but possibly more confusing to some.
He went
on to say:
It
would mean that you could stop your motorcycle in a total of 5.4
seconds (including the 1 second delay.) and your total stopping
distance would be only 281.5 feet!
If
you'll look at any road test of a current production motorcycle
you'll see that stopping distances from 60 mph are typically 120 -
140 feet. Cages are frequently in the 150 - 180 foot range.
As to
his suggestion that I recheck my math, I did, and obtained the same
results.
So that
there is no confusion, my message argued the point that by increasing
your braking skills you could significantly reduce both the time it
takes to stop and the distance taken to stop your motorcycle. Further,
though I acknowledged that a motorcycle racer could get 1g
deceleration (32 fpsps), or more, a reasonably skilled rider could
easily get deceleration rates in excess of 20 fpsps. And, by contrast,
showed what Traffic Engineers use as an assumption of safely
attainable deceleration rates by the average person (15 fpsps).
So, I
was not saying that you should (or can) try to get 1g deceleration
rates, but that you can and should get much better braking (safely)
than 'average' with just a little practice.
As to
the numbers:
To
determine how long it will take you to stop assuming a constant rate
of deceleration, you need only divide your starting velocity (in fps)
by your rate of deceleration.
60 MPH =
88 fps. (fps=1.467 * MPH). If your deceleration rate is 20 fpsps,
then stopping time = 88/20 = 4.4 seconds. Since there is a 1 second
delay in hitting your brakes (recognition and reaction time), the
total time to stop is 5.4 seconds, just as I said.
To
determine how far you will travel while braking you take 1/2 the
starting velocity and multiply the result by the stopping time (ie,
you calculate your average speed and multiply by how long you are
moving.) In the cited case, this works out to be:
.5 * 88
* 4.4 = 193.6 feet. Since we traveled 88 feet before we hit the
brakes, we add that to 193.6 and end up with a total of 281.6 feet,
as I said (missed by .1 feet.)
So, how
can my numbers be so far off from those reported? Simple. Clearly they
are reporting JUST stopping distance and with deceleration rates of
about 1 g. [Rider magazine once reported the results of stopping a
Yamaha from 60 MPH AVERAGED 87 feet in a series of nine attempts. That
was stopping at the rate of over 44 fps/s or approximately 1.3 g.]
Assuming
a deceleration rate of 32 fpsps (1g), we calculate a braking stop time
of 2.75 seconds (88/32). Distance traveled now is calculated to be 121
feet. (Ignoring the additional 88 feet you traveled before applying
your brakes.) This is consistent with published reports, as he
presented them.
The
math is easy, the message is too - Skillful braking can save your
life.
For
those of you that are into math, I full well realize that I used an
approximation for distance traveled when I simplified my formula and
assumed an 'average speed'. Since the correct formula which would take
the deceleration rate into account is beyond some of the readers, I
chose to make it simple - because the message is also simple.
(Besides, it yields the same answer.)
If you
are interested, to calculate the distance using deceleration rates you
would use:
x = x0
+ (v0 * t) - (1/2 * a * tē)
where:
x = distance traveled (feet)
x0 = starting distance (feet - for example, recognition/reaction
distance of 88)
v0 = initial velocity (feet per second)
t = stopping time (seconds)
a = deceleration rate (feet per second per second)
Return
to

|