100A QUIZ 4
Solution. Because this is a perfect inelastic
collision two balls stick together after the collision,
From conservation of momentum we have m1v1 + m2v2 = (m1 +m2)V; (2kg)(35m/s) + (15kg)(-2m/s) = (2kg + 15kg)V, which gives V = 2.35m/s. We find the energy of the system after the collision from KE = 1/2(m1 +m2)V2 = 1/2(2kg + 15kg)(2.35m/s)2 = 47.1J |
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Solution. We find the pressure due to the seawater from
Psea = rseawatergh = (1.025 x103kg/m3)(9.80m/s2)(100m) = 1.0045 x106N/m2 = 1.0045 x106pa
Thus the total pressure on the top of the submarine is
Pair + Psea = 101.3kpa + 1.0045 x106pa = 1.106 x106pa.