100A QUIZ 7
Solution.
From the conservation of momentum we have
m1v1 + m2v2 = m1v1' + m2v2';
(5.0kg)(4.0m/s) + (3.0kg)(0) = (5.0kg)v1' + (3.0kg)v2'
Because the collision is perfect elastic we have v1 - v2 = -(v1' - v2') or 4.0m/s - 0 = v2'- v1'.
Combining the two equations we get
v1' = 1.0m/s. and v2' =5.0m/s. (in the same direction.)
Solution.
From the conservation of momentum we have
m1v1 + m2v2 =( m1 + m2)V;
(1500kg)(45km/h)/(3.6ks/h) + 0 = (1500kg +2000kg)V,
which gives V = 5.3m/s = 19km/h.