QUIZ 8
Solution.
Choose the coordinate system as shown with m3 as the origin. We find the center of mass from xCM = (m1x1 + m2x2 + m3x3)/(m1 + m2+ m3) = [(5kg)(-20cm) + (2kg)(0) + (4kg)(0)]/(5kg + 2kg + 4kg) = -9.1cm yCM = (m1y1 + m2y2 + m3y3)/(m1 + m2+ m3) = [(5kg)(20cm) + (2kg)(20cm) + (4kg)(0)]/(5kg + 2kg + 4kg) = 12.7cm The center of mass of the system is at -9.1cm to the left and 12.7cm above m3. |
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Solution.
We find the angular acceleration from
q = q0 + w0t + 1/2at2;
2p(200rev)(rad/rev) = 0 + 0 + 1/2a[(2.5min)(60s/min)]2,
which gives a = 0.11rad/s2.