Answers to the homework:

Ex.6: mean= (182.4 + 182.2 + 182.5 + 182.7 + 182.4 + 182.4 + 182.2)/7 = 182.40cm
          182.4cm-182.40cm = 0.0cm
          182.2cm-182.40cm = -0.2cm
          182.5cm-182.40cm = 0.1cm
          182.7cm-182.40cm = 0.3cm
          182.4cm-182.40cm = 0.0cm
          182.4cm-182.40cm = 0.0cm
          182.2cm-182.40cm = -0.2cm
                   Sum = 0.00cm

Ex.7: s = Ö{[0 +(-0.2)2+(0.1)2+(0.3)2+0+0+(-0.2)2]cm2/(7-1)} = 0.17cm

Ex.9.: mean = (W1+W2+W3+W4+W5+W6+W7+W8)/(8-1) = 1.985 x 10-4N
        sw = Ö{[(1.96 x10-4-1.985 x 10-4)2+(1.964 x 10-4-1.985 x 10-4)2 +. . . ]/(8-1)} = 0.029 x 10-4N
        Gaussian distribution is between 1.985 x 10-4 +0.029 x 10-4 = 2.014 x 10-4N and
        1.985 x 10-4N - 0.029 x 10-4N = 1.956 x 10-4N, 6 measurements are within the distribution.

Ex.11: mean = (0 x 2 + 1 x1 + 2 x9 + 3 x14 + 4 x 16 + 5 x19 + 6 x 12 + 7 x 18 + 8 x 2 + 9 x 1 + 10 x 0 )/84 = 4.44

        s N = Ö{[2 x(0-4.44)2 + 1 x (1-4.44)2 + ...]/(84-1)} = 1.81

Ex.12: V = LWH =(10.13ft)(1.534ft)(0.013ft) = 0.202ft3
        V = 1 x L1W1H1
        sv2/V2 = sL2/L2 + sw2/W2 + sH2/H2
        sv =[(0.01ft)2/(10.13ft)2 + (0.002ft)2/(1.543ft)2 +(0.001ft)2/(0.0131ft)2]/(0.202ft3)2 = 0.016ft3.

Ex.14: P+ = 2 x (26cm +16cm) = 84cm
            P- = 2 x (24cm + 14cm) = 76cm
           sp = (84cm - 76cm)/2 = 4cm.

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