Take the isosceles triangle ABC with AC = AB.
Point D on side CB is such that
the triangles CDA and DBA are isosceles
with CD = AD, and DB = AB.
1. Find the angles of the triangle ABC.
2. Prove that the area of the triangle DBA equals
the geometric mean of the areas of the triangles
CDA and ABC: =
.
3. Prove that point D divides the side CB
in the golden ratio.
Answers:
1. The angles ACD and ABD equal 36 deg, the angle BAC equals 108 deg.
2. :
:
=
.
3. CD : DB = DB : CB.