The right triangle:
      Concurrence of altitude, median and bisector

   The problem:
   Let ABC be the triangle with the right angle ACB.
   The median AD, the bisector BE, and the altitude CF meet at the point S.
   Find the side-to-hypotenuse ratio CB/AB

[Graphics:Images/concur_gr_1.gif]

             Hint:
             The line EF is parallel to the side CB.
  

            Answer:

[Graphics:Images/concur_gr_2.gif]

          the  golden ratio.

          Proof:
          N/A


Converted by Mathematica      December 31, 2001