2 chevians make the triangle of area
larger than 1/2 area of the right triangle
In the right triangle ABC, with angle C = 90 deg,
a point P is inside the ABC;
two chevians, APD and CPE, make triangle APE
with area equal to s-th part of area of the triangle ABC:
area(APE)=s area(ABC).
(If point P is distributed inside the ABC
randomly with uniform probability density,)
what is the probability that s>1/2?
Answer is
but better try youself!