Solid: Cube
Cut 1: Vertex
Sequence: C
Term: 2
| Name | Number | Colors | Permutation | Orientation | Orbits |
| Corner | 8 | 3 | Even | 3, Fixed | 2, Immobility |
| Face | 6 | 1 | Even | N/A | 1 |
Slice Summary
| Cut Type | Layer | Period | Pieces Affected | Total Parity |
| Vertex | 1 | 3 | 1. 1 Corner Twist 2. 1 Corner Three Cycle 3. 1 Face Three Cycle |
Even |
Method 1
The method works by solving one half intuitively then the last half by piece type. Mike Tryczak provides algorithms for solving the last half in one step here as part of his speed-skewbing solution. The algorithms presented on this page are what I have so far been able to construct myself.
Step 1 - Solve two Corners and two Faces
Solve two corners and the two faces which belong between them.
Step 2 - Complete First Layer
To complete the first layer, solve a group of two corners and one face next to the group solved in step one. This step is intuitive but takes a bit of getting used to.
Step 3 - Solve last half permutation
With at most twist, correctly place all remaining unsolved corners. This will leave the last three faces either solved or three-cycled. Apply the following algorithm to fix them. It is a commutator but there is a move cancellation at the beginning. The last half should be in the BR slice, and written it cycle centers couterclockwise. When using the inverse, the last half should be in the BL slice.
Three cycle centers (HSN): (F- U+ F-) D+ (F+ U- F-) D- B-
Step 4 - Orient Corners
Finish the puzzle by orienting the corners. There are three possibilites: solved, two corners twisted opposite ways, or three corners twisted the same way. Use the following algorithms. The two corner twist has the last half in the R or L slice; the three corner twist has the last half in the UFR slice.
Twist two corners (HSN): (R- L+ R+ L-) U+ (L+ R- L- R+) U-
Twist three corners: (UFL+ UFR+ DFR+) x 3