Attach 2

 

Home

 

DECODING SCHEME

IN THE MOLECULE OF

 INSULIN

 

Fragment 58

Molecule of insulin

Chain A

Phe,(F), Val(V), Asn(N), Gln(Q), His(H), Leu(L), Cys(C),

Gly(G), Ser(S), His(H), Leu(L), Val(V), Glu(E), Ala(A), Leu(L),

Tyr(Y), Leu(L), Val(V), Cys(C), Gly(G), Glu(E), Arg(R), Gly(G),

Phe(F), Phe(F), Tyr(Y), Thr(T), Pro((P), Lys(K), Ala(A)

Chain B

Glu(E), Ileu(J), Val(V), Glu(E), Gln(Q), Cys(C), Cys(C), Ala(A),

Ser(S), Val(V), Cys(C), Ser(S), Leu(L), Tyr(Y), Gln(Q), Leu(L),

Glu(E), Asn(N), Tyr(Y), Cys(C), Asn(N),

Number of atoms:

Chain A

F=23; V=19; N=17, Q=20; H=20; L=22; C=14; G=10; S=14; H=20;

L=22; V=19; E=19; A=13; L=22; Y=23; L=22; V=19; C=14; G=10;

E=19; R=25; G=10; F=23; F=23; Y=23; T=17; P=17; K=24;

A=13; = 556 atoms.

Chain B

E=19; J=22; V=19; E=19; Q=20; C=14; C=14; A=13; S=14; V=19;C=14;

S=14; L=22; Y=23; Q=20; L=22; E=19; N=17; Y=23; C=14; N= 17;=378 atoms;

Decoding formula:

[S19(X1 + X2 + X3 ...+ Xn)] = 931;

X1,2,3,n = Number of atoms in amino acids 1,2,3,n;

Example 1

X1 = Thr(T) = 17 atoms; X2 = Pro(P) = 17 atoms;

X3 = Lys(K) = 24 atoms;

S19(17 atoms+ 17 atoms + 24 atoms) = S19(58) atoms;

S19(58) = (40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55 + 56 + 57 +58) = 931;

Example 2

X1 = Arg(R) = 25 atoms; X2 = Gly(G) = 10 atoms;

X3 = Phe(F) = 23 atoms;

S19(25 atoms+ 10 atoms + 23 atoms) = S19(58) atoms;

S19(58) = (40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55 + 56 + 57 +58) =

= 931;

Example 3

X1 = Ala(A) = 13 atoms; X2 = Leu(L) = 22 atoms;

X3 = Tyr(Y) = 23 atoms;

S19(13 atoms + 22 atoms + 23 atoms) = S19(58) atoms;

S19(58) = (40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55 + 56 +

+ 57 +58) = 931;

Example 4

X1 = Cys(C) = 14 atoms; X2 = Gly(G) = 10 atoms;

X3 = Ser(S) = 14 atoms; X4 = His(H) = 20 atoms;

S19(14 atoms + 10 atoms + 14 atoms + 20 atoms) =

 = S19(58) atoms;

S19(58) = (40 + 41 + 42 + 43 + 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55 + 56 + 

+ 57 +58) = 931;

Etc.

Fragment 136

Decoding formula:

[S7(X1 + X2 + X3 ...+ Xn)] =931;

X1,2,3,n = Number of atoms in amino acids 1,2,3,n;

Example 1

X1 = Phe(F) = 23 atoms; X2 = Val(V) = 19 atoms;

X3 = Asn(N) = 17 atoms; X4 = Gln(Q) = 20 atoms;

X5 = Cys(C) = 14 atoms; X6 = Gly(G) = 10 atoms;

X7 = Gly(G) = 10 atoms; X8 = Phe(F) = 23 atoms;

S7(23 + 19 + 17 + 20 + 14 + 10 + 10 + 23) = S7(136);

S7(136) = (130 + 131 + 132 + 133 + 134 +

+ 135 + 136) = 931;

Example 2

X1 = His(H) = 20 atoms; X2 = Leu(L) = 22 atoms;

X3 = C ys(C) = 14 atoms; X4 = Gly(G) = 10 atoms;

X5 = Tyr(Y) = 23 atoms; X6 = Thr(T) = 17 atoms;

X7 = Pro(P) = 17 atoms; X8 = Lys(K) = 24 atoms;

S7(20 + 22 + 14 + 10 + 23 + 17 + 17 + 13) = S7(136);

 

S7(136) = (130 + 131 + 132 + 133 + 134 + 

+135 + 136) = 931;

Etc.

 

Home | MATRIX CODE | G E N O M E  2 | I N S U L I N | N  E  W | Contact Information

 Copyright EMER® Research project 1985 - 2001
For problems or questions regarding this web contact Manager.
Last updated: 08/22/01.