N E W  3

 

Home

 

DECODING SCHEME

IN THE MOLECULE OF

 INSULIN

C o d e s 7 and 931

 

Molecule of insulin

Chain A

Phe,(F), Val(V), Asn(N), Gln(Q), His(H), Leu(L), Cys(C),

Gly(G), Ser(S), His(H), Leu(L), Val(V), Glu(E), Ala(A), Leu(L),

Tyr(Y), Leu(L), Val(V), Cys(C), Gly(G), Glu(E), Arg(R), Gly(G),

Phe(F), Phe(F), Tyr(Y), Thr(T), Pro((P), Lys(K), Ala(A)

Chain B

Glu(E), Ileu(J), Val(V), Glu(E), Gln(Q), Cys(C), Cys(C), Ala(A),

Ser(S), Val(V), Cys(C), Ser(S), Leu(L), Tyr(Y), Gln(Q), Leu(L),

Glu(E), Asn(N), Tyr(Y), Cys(C), Asn(N),

 

Number of atoms:

Chain A

F=23; V=19; N=17, Q=20; H=20; L=22; C=14; G=10; S=14; H=20;

L=22; V=19; E=19; A=13; L=22; Y=23; L=22; V=19; C=14; G=10;

E=19; R=25; G=10; F=23; F=23; Y=23; T=17; P=17; K=24;

A=13; = 556 atoms.

Chain B

E=19; J=22; V=19; E=19; Q=20; C=14; C=14; A=13; S=14; V=19;C=14;

S=14; L=22; Y=23; Q=20; L=22; E=19; N=17; Y=23; C=14; N= 17;=378 atoms

Decoding formula:

[ S7(X1) + S7(X2) + S7(X3) + S7(X4)] + +S7(X1+X2+X3+X4) = 931;

X1, X2, X3, X4 = Number of atoms in aminoacids X1,2,3,4;

Chain “A”

Example 1

X1 = His(H) = 20 atoms;

X2 = Leu(L) = 22 atoms;

X3 = Glu(E) = 19 atoms;

X4 = Ala(A) = 13 atoms;

 S7(20) + S7(22) + S7(19) + S7(13)] + +S7(20+22+19+13) = 931;

[ S7(20) + S7(22) + S7(19) + S7(13)] + +S7(74) = 931;

................

S7(20) = (14+15+16+17+18+19+20) = 119;

S7(22) = (16+17+18+19+20+21+22) = 133;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(13) = (7+8+9+10+11+12+13) = 70;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (119 + 133 + 112 + 70)+ 497] = 931;

……………….

Example 2

X1 = Val(V) = 19 atoms;

X2 = Cys(C) = 14 atoms;

X3 = Pro(P) = 17 atoms;

X4 = Lys(K) = 24 atoms;

 

[ S7(19) + S7(14) + S7(17) + S7(24)] + +S7(19+14+17+24) = 931;

[ S7(19) + S7(14) + S7(17) + S7(24)] + +S7(74) = 931;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(14) = (8+9+10+11+12+13+14) = 77;

S7(17) = (11+12+13+14+15+16+17) = 98;

S7(24) = (18+19+20+21+22+23+24) = 147;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (112 + 77 + 98 + 147)+ 497] = 931;

……………….

Example 3

X1 = Leu(L) = 22 atoms;

X2 = Val(V) = 19 atoms;

X3 = Gly(G) = 10 atoms;

X4 = Phe(F) = 23 atoms;

[ S7(22) + S7(19) + S7(10) + S7(23)] + +S7(22+19+10+23) = 931;

[ S7(22) + S7(19) + S7(10) + S7(23)] + +S7(74) = 931;

S7(22) = (16+17+18+19+20+21+22) = 133;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(10) = (4+5+6+7+8+9+10) = 49;

S7(23) = (17+18+19+20+21+22+23) = 140;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (133 + 112 + 49 + 140)+ 497] = 931;

……………….

Example 4

X1 = Phe(F) = 23 atoms;

X2 = Val(V) = 19 atoms;

X3 = Glu(E) = 19 atoms;

X4 = Ala(A) = 13 atoms;

[ S7(23) + S7(19) + S7(19) + S713)] + +S7(23+19+19+13) = 931;

[ S7(23) + S7(19) + S7(19) + S7(13)] + S7(74) = 931;

S7(23) = (17+18+19+20+21+22+23) = 140;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(13) = (7+8+9+10+11+12+13) = 70;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (140 + 112 + 112 + 70)+ 497] = 931;

……………….

Etc.

Chain “B”

X1 = Glu(E) = 19 atoms;

X2 = Ileu(I) = 22 atoms;

X3 = Ser(S) = 14 atoms;

X4 = Val(V) = 19 atoms;

 S7(19) + S7(22) + S7(14) + S7(19)] + +S7(19+22+14+19) = 931;

[ S7(19) + S7(22) + S7(14) + S7(19)] + S7(74) = 931;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(22) = (16+17+18+19+20+21+22) = 133;

S7(14) = (8+9+10+11+12+13+14) = 77;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (112 + 133 + 77 + 112)+ 497] = 931;

……………….

Example 2

X1 = Val(V) = 19 atoms;

X2 = Glu(E) = 19 atoms;

X3 = Glu(E) = 19 atoms;

X4 = Asn(N) = 17 atoms;

[ S7(19) + S7(19) + S7(19) + S7(17)] + +S7(19+19+19+17) = 931;

[ S7(19) + S7(19) + S7(19) + S7(17)] + +S7(74) = 931;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(17) = (11+12+13+14=15=16=17) = 98;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (112 + 112 + 112 + 98)+ 497] = 931;

……………….

Example 3

X1 = Val(V) = 19 atoms;

X2 = Glu(E) = 19 atoms;

X3 = Ser(S) = 14 atoms;

X4 = Leu(L) = 22 atoms;

[ S7(19) + S7(19) + S7(14) + S7(22)] + +S7(19+19+14+22) = 931;

[ S7(19) + S7(19) + S7(14) + S7(22)] + S7(74) = 931;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(14) = (8+9+10+11+12+13+14) = 77;

S7(22) = (16+17+18+19+20+21+22) = 133;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (112 + 112 + 77 + 133)+ 497] = 931;

……………….

Example 4

X1 = Val(V) = 19 atoms;

X2 = Cys(C) = 14 atoms;

X3 = Leu(L) = 22 atoms;

X4 = Glu(E) = 19 atoms;

[ S7(19) + S7(14) + S7(22) + S719)] + +S7(19+14+22+19) = 931;

[ S7(19) + S7(14) + S7(22) + S7(19)] + +S7(74) = 931;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(14) = (8+9+10+11+12+13+14) = 77;

S7(22) = (16+17+18+19+20+21+22) = 133;

S7(19) = (13+14+15+16+17+18+19) = 112;

S7(74) = (68+69+70+71+72+73+74) = 497;

 

[ (112 + 77 + 133 + 112)+ 497] = 931;

……………….

Etc.

Attach:

Chain “A” has 556 atoms, and chain “B” has 378 atoms.

Decoding scheme:

[ S7(556) + S19(556) + S7(378) + S19(378)] =

=(3871 + 10393 + 2625 + 7011) = 23900;

Codes 19 and 7

23900 = { (19 x 7) + [ (1907 + 719) + (1907 + 719) + (1907 + 719) + +(1907 + 719)] + (719 + 1907) + (719 + 1907) + [ (719 + 1907) + (719 + +1907) + (719 + 1907)] + (7 x 19)} ;

……

 

 

 

 

 

 

 

 

 

Home MATRIX CODE G E N O M E  2 I N S U L I N N  E  W Contact Information

 Copyright EMER® Research project 1985 - 2001
For problems or questions regarding this web contact Manager.
Last updated: 08/21/01.