Mass Transfer
1. What are the advantages of distillation over absorption?
2. Define the term relative volatility
3. State Henry's law
4. What is Murphree tray efficiency?
5. What is meant by equilibrium distillation?
6. What is absorption factor?
7. What is molecular distillation?
8. Sketch the operating line and equilibrium curve for an absorber and stripper
9. What is meant by minimum liquid gas ratio?
10. What is plait point?
11. Explain percolation method of leaching?
12. Define distribution coefficient and state its importance
13. What is electrodialysis?
14. What are the properties of solvent for extraction?
15. What is ion retardation?
16. Mention few industrial adsorbents
17. What is adsorption hysteresis?
18. Write the principle of ion-exchange
19. What is meant by constant molal over flow?
20. What is the role of Raoult's law in distillation?
Part B
21. (a) Write short notes on:
(i) Azeotropic distillation
(ii) Extractive distillation
(iii) Rayleigh's equation
Or
(b) A binary mixture of benzene and toluene containing 40% of benzene is to be distilled at 1 atm pressure to recover 95% of the benzene. Estimate the molal percent of mixture to be distilled and the composition of the distillate obtained if distillation is carried out by
(i) Equilibrium distillation
(ii) Differential distillation, collecting all the distillate together.
The average relative volatility of benzene to toluene is 2.5.
22. (a) Explain in detail, the method of estimation of number of stages by Mc Cabe - Thiele method.
Or
(b) A continuous fractionator is to be designed for separating a feed mixture containing equimolar amounts of CCl4 and CS2 to get a top product containing 95% CS2 and bottom product containing 6% CS2 at 1 atm pressure. The feed is saturated vapor and fed at the rate of 5000 kg/hr. A total condenser is used and reflux is returned to the top plate as a saturated liquid. The equilibrium data is given below:
|
x |
0.06 |
0.11 |
0.26 |
0.39 |
0.53 |
0.66 |
0.76 |
0.86 |
1 |
|
y |
0.16 |
0.27 |
0.50 |
0.63 |
0.75 |
0.83 |
0.88 |
0.93 |
1 |
(i) Determine the flow rate of top and bottom product
(ii) Calculate the theoretical number of trays required if a reflux ratio of 2 times Rm is used.
(iii) Locate the feed tray.
23. (a) Derive an expression for the number of plates in terms of absorption factor.
Or
(b) The experimental data given below are obtained for the absorption of ammonia from air into water using a 2.5 cm diameter Rasching rings packed in a 25 cm diameter up to 2 m. The total pressure is 1 atm and the average temperature is 20oC. Air flow rate excluding ammonia is 105 m3/hr and the water flow rate is 400 kg/hr. Ammonia concentration in the gas inlet is 7% and in the outlet is 0.314%. The interfacial area of packing is 185 m2/m3. Partial pressure of ammonia at equilibrium with the solution at the bottom is 0.011 atm and at the top is zero/since pure water is used. Assuming that both equilibrium and operating line are straight, calculate:
(i) Overall mass transfer coefficient for the system.
(ii) The number of overall gas phase transfer unit.
(iii) The height of overall gas phase transfer unit.
24. (a) With neat sketch, explain the working of Bollman extractor.
Or
(b) An aqueous solution of solute C is to be extracted with pure solvent B to recover the solute. The equilibrium data in terms of weight % of solute in the two layers are given below:
|
Aqueous layer |
2 |
8 |
15 |
20 |
|
Solvent layer |
8 |
22 |
35 |
45 |
A feed 20% by weight of solute is to be treated in two consecutive cross current cascades using aqueous solution to solvent ratio of 1.8. Calculate:
(i) Concentration of final raffinate
(ii) Amount of raffinate
(iii) % recovery of solute
(iv) Amount of solvent to be used for a single stage extraction to obtain the same final concentration.
Water and solvent are immiscible with each other.
25. (a) Write short notes on:
(i) Electrodialysis
(ii) Ultrafiltration
(iii) Reverse osmosis
Or
(b) The equilibrium absorption of acetone vapor on activated carbon at 30oC is given below:
|
Acetone partial pressure, in mm Hg |
2 |
12 |
42 |
92 |
|
Gram acetone/Gram carbon |
0.1 |
0.2 |
0.3 |
0.35 |
The vapor pressure of acetone at 30oC is 283 mm Hg. A one litre flask containing air and acetone mixture at 1 atm is fed with 2 gram of activated carbon and then sealed. Compute the final vapor concentration and the final pressure. Neglect the adsorption of air.
1.
(a) Simplify
the Fick's law of mass diffusion for equimolar counter diffusion for a binary
system.
(b) In a gas mixture of hydrogen and oxygen, steady state equimolar counter
diffusion is occuring at a total pressure of 100 kPa and temperature of 20oC.
If the partial pressures of oxygen at two planes 0.01m apart, and perpendicular
to the direction of diffusion are 15 kPa and 5 kPa, respectively and the mass
diffusion flux of oxygen in the mixture is 1.6 x 10-5 kmole/(m2.sec),
Calculate the molecular diffusivity for the system.
2.
Carbon
disulfide is to be absorbed from a dilute gas mixture of CS2 - N2
into a pure nonvolatile oil at atmospheric pressure in a counter current
absorber. The molefraction of CS2 in inlet gas stream is 0.05 and the
flow rate of gas stream, G is 1500 kmol/hr. The equilibrium relation is given
by:
y = 0.5x
where x is the molefraction of CS2 in liquid stream. It is desired
to reduce the mole fraction of CS2 in the exit gas stream to 0.005.
(a) Calculate the minimum value of L/G where L is the liquid flow rate in
kmol/hr.
(b) Derive the equation for the operating line if L/G is equal to 1.5 times the
minimum value.
3.
A liquid
mixture containing 50 mole % each of benzene and toluene at 40oC is to
be continuously flash vaporized to vaporize 60 mole % of the feed. The residual
liquid product contains 35 mole % benzene. If the enthalpies per mole of feed,
the liquid product and the vapor product are respectively 2,5 and 30 kJ/mole,
(a) calculate the heat added in kJ per
mole of vapor product
(b) represent the process on a H-x-y
diagram
4.
160 kg of
wet solid is to be dried from an initial moisture content of 25% to a final
value of 6%. Drying test shows that the rate of drying is constant at 3 x 10-4
kg H2O / m2.s in the region 0.2 - 0.4 4 kg H2O
/ kg solid. The drying rate falls linearly in the range 0.01 - 0.2 kg H2O
/ kg solid. If the equilibrium moisture content is 0.01 kg H2O / kg
solid, calculate the time of drying. The drying surface is 1 m2 / 30
kg dry weight.
5.
A material
having a critical moisture content of 24% is dried under constant drying
conditions in slabs of dimensions 20cm x 20cm x 2cm from a moisture content of
40% to 25% in 8 hours. Drying takes place from the two larger surfaces only.
The same material is dried in slabs of 40cm x 40cm x 4cm under similar drying
conditions from 50% to 25% moisture content. All moisture content are on wet
basis. If the critical moisture content and other physical properties remain
unchanged, how long will the drying take?
6.
In a
laboratory drying test with a solid material the following relation for the
falling rate period was obtained,
dX/dq = -0.8 (X - 0.05)
where X is the moisture content on dry
basis and q is the time in hours. The critical
moisture content is 1.4 kg moisture per kg of dry material. Calculate:
a.
the time
required for drying the material from X1 = 4.0 to X2 =
0.1
b.
the
equilibrium moisture content.
7.Drying of a food product is carried out in an insulated tray.
The drying air has a partial pressure of water equal to 2360 Pa and a wet bulb
temperature of 30oC. The product has a drying surface of 0.05 m2/kg
dry solid. The material has a critical moisture content of 0.12 (dry basis) and
negligible equilibrium moisture content. The drying rate in the falling rate
period is proportional to the moisture content and the mass transfer
coefficient is 5.34 x 10-4 kg/m2hrPa. Calculate:
a.the drying rate in the constant rate period in kg/m2hr
b.
the time
required to dry the material from a moisture of 0.22 to 0.06 (both on dry
basis).
Vapor pressure of water at 30oC = 4232 Pa.
Rate of entering air
= 13.6 m3/min
Rate of entering
water = 1000 kg/hr
Humidity of entering
air = 0.0175 kg water vapor / kg dry air
Latent heat of
evaporation of water = 589 kcal/kg
Specific heat of air
= 0.245 kcal/kgoC
Specific heat of
water vapor = 0.45 kcal/kgoC
Data:
Saturated humidity
at 32.2oC = 0.025 kg water/kg dry air
Specific volume of
dry air at 54oC = 0.925 m3/kg
Saturated volume =
1.09 m3/kg
Humid heat 0.015
humidity = 0.243 cal/gmoC
Humid heat at 32.2oC
and at 80% saturated humidity = 0.250 cal/gmoC
Saturation humidity
at 70oC = 0.299
Humid heat of inlet
air = 0.243 cal/gmoloK
The saturation vapor
pressure of acetone at 25oC is 290 mm Hg and the specific heats of
oxygen and acetone vapor are 0.25 and 0.35 kcal/kgoC respectively.
|
t oC |
24 |
29 |
32.5 |
38 |
43.5 |
|
H |
20 |
25 |
28 |
36 |
46 |
Note: For air water
system CS (humid heat) = 0.24 + 0.45 Y'
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Last Updated: 03/10/03
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