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WEEK 15: FINAL CORRECTING DEVICES: AMPLIFIERS Sections: Basic | Circuits | Op-Amps Definition. A circuit whose output is proportional to how quickly the in put is changing.
1. If VIN is a steady dc output, capacitor will charge to VIN. No current will flow through capacitor, C, or the feedback resistor, RF. Therefore: VOUT = zero. 2. If VIN is a slowly changing voltage, VC is slightly equal to VIN. The current at the capacitor, IC and the feedback resistor, IRF will be relatively small, thus VOUT will also be relatively small. 3. If VIN is a rapidly changing voltage, VC is much less than VOUT, because the capacitor will have no time to charge. The current at the capacitor, IC and the feedback resistor, IRF will be very large, thus VOUT will also be a large voltage. Therefore, in an Integrator Op-amps, the rate of change in the magnitude of VIN is proportional to the magnitude of VOUT. |
