Go Where Ya Need To!
Answers to previous problems are down below. Just scroll down for them. Scroll carefully because the questions come up first, so if you want to try them before you see the answer, don't scroll all the way down.
This problem was taken from the magazine: Mathematics Teaching in the Middle School. January 1999.
Prepared by DAVID SPANGLER, firstname.lastname@example.org. Spangle teaches at National-Louis University Evanston, IL 60201. He is also an editorial manager for a textbook publishing company and is always looking for ways to teach mathematics through engaging, real world applications.
SOMETHING IS WRONG WITH EACH OF THE advertisements to the right. Are the mistakes honest errors ... or is someone trying to "pull the wool over our eyes"? Sometimes it is hard to tell for sure. But we can put on our detective hat to investigate what these advertisements are saying mathematically. The questions that follow will help us determine whether the bananas are "a-peeling," whether the lamps are a "shady" deal, and whether the CDs should be "music to your ears."
Questions Advertisement 1
1. For advertisement 1 how much money is .49¢?
a) 49 cents b) $0.49 c) about a half cents
d)$O.049 e) S0.0049
2. Explain whether a customer would be mathematically correct in telling the clerk, "I'd like to buy two pounds of bananas. Here is one cent. You can keep the change."
3. How would you correct advertisement 1?
4. For advertisement 2, let us consider this situation. Suppose that a lamp regularly sells for $120.
a) What would the lamp cost after a first discount of 60 percent is applied?
b) What would the lamp cost after the second discount, 25 percent, is applied to the discounted price in question 4a?c) How much money would you save with the two discounts? The total dollar savings is what percent of the original selling price?
d) How did the advertising agent arrive at 85 percent? How would you explain to him or her why this amount is incorrect?
Advertisement 35. In advertisement 3, how much would a CD cost if it was discounted at "only" 100 percent off the list price?
6. What is the correct percent discount for the CDs? Round your answer to the nearest tenth of a percent.
7. If a CD really sold at 714 percent off the list price, how much would the store have to pay you if you "bought" the CD?
Here is a chance for you to become a mathematics detective in your neighborhood. Hunt for misleading or mathematically incorrect advertisements. Such advertisements may be found in newspapers, direct mail promotions, on television, in stores, and so on. Bring them to class for discussion. Then send your favorites to the address that follows. Selected advertisements will be the topic of a future "Mathematics Detective" article. Copies or descriptions of the advertisements are sufficient when actual advertisements cannot be sent. Send advertisements to me by email or by snail mail (regular mail). If you are one of my students bring them into school. (1point extra credit for each with explanation of what's wrong.)email@example.com
Answers for Ad #1: 1) c and e. The amount .49¢ is forty-nine hundreths of one cent. 2) The customer would be correct, for a pound would cost $0.0098, or 98 hundreths of one cent. 3) The price should be marked as either 49¢/lb or $0.49/ lbs.
Answers for Ad #2: 4a) 60% would be .60 x 120 or $72 so $120 - $72 = $48. 4b) When the second discount is applied to the now $48 an additional .25 x $48 or $12 is deducted, so $48 - 12 = $36. 4c) Since the final price is $36, a customer is saving $120 -$36 or $84. This would be 84/120 ( / means divide) or 70% savings. 4d) The advertising agent added the two percents. Of course he is wrong!!! One must calculate each percent separately and in order.
Answers for Ad #3: 5) At 100% the CD would be free!!! 6) The savings would be $13.95 - $3.99, or $9.96. The percent savings is 9.96/ 13.95 or 0.71397... or about 71.4% 7) This one is very cool... At 714% off the store would owe you money. The first 100% would take it down to $0 and the remaining 614% would be 6.14 x 13.95 or about $85.65. That's how much they would have to pay YOU!!!
1. What number is this? MDCCLXXVI It is on a famous monument.
2. What Roman numbers of two integers between one and twenty become larger whe the left-hand interger is omitted?
Answer to number 1 is 1776 and number 2 is IV (4) and IX (9).